Java 从路径或者链接 url 字符串中获取文件名
描述
从路径或者链接 url 的字符串中获取文件名,先删除 url 中 ?
后面的字符,也就是请求参数,再截取最后一个路径分隔符之后的部分,Windows 系统的分隔符为 \
,Unix/Linux 分隔符为 /
。实现的代码如下:
public class Filename {
public String basename(String str) {
if (str == null) {
return "";
}
int questionIndex = str.indexOf("?");
if (questionIndex != -1) {
str = str.substring(0, questionIndex);
}
// The Unix separator character.
char unixSeparator = '/';
// The Windows separator character.
char windowsSeparator = '\\';
final int lastUnixPos = str.lastIndexOf(unixSeparator);
final int lastWindowsPos = str.lastIndexOf(windowsSeparator);
int lastIndex = Math.max(lastUnixPos, lastWindowsPos);
return str.substring(lastIndex + 1);
}
}
调用示例
public static void main(String args[]) {
String url = "https://www.google.com/search/LRV_20210130_162218_11_014.insv?key=AADLg2BQJuGQQ06tGxJ-xQnJa&dl=0&preview=1";
String path1 = "/Users/apple/Downloads";
String path2 = "D:\\Downloads\\test.data";
String path3 = "D:\\Downloads\\test";
Filename filename = new Filename();
System.out.println(filename.basename(url)); // LRV_20210130_162218_11_014.insv
System.out.println(filename.basename(path1)); // Downloads
System.out.println(filename.basename(path2)); // test.data
System.out.println(filename.basename(path3)); // test
}
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